Question

using remainder theorem factorise 2x^3-9x^2-11x+30 ​

Answer 1

Answer:

x = +5 , -2 , +3/2

Step-by-step explanation:

p(x) = 2x³ - 9x² - 11x + 30

let p(x) = -2

           = 2(-8) - 9(4) - 11(-2) + 30

           = -16 - 36 + 22 + 30

           = - 52 + 52

           = 0

therefore one zero of the polynomial is (x + 2),

dividing (x + 2) by p(x),

SEE THE ATTACHMENT,

now we got the new equation

i.e. , 2x² - 13x + 15

       2x² - 10x - 3x + 15

       2x(x - 5) - 3(x - 5)

       (x - 5)(2x - 3)

all the zeroes of the polynomial are ,

(x - 5)(2x - 3)(x + 2)

x = +5 , -2 , +3/2