Question

using remainder theorem factorise : 6x³- 25 x ² + 32x-12

Answer 1

6x^3-25x^2+32x-12

for this we can see that x=2 is a zero of this  6(2)^3-25(2)^2+32(2)-12=0

so we can say (x-2) is factor of 6x^3-25x^2+32x-12

Divide by 6x^3 -25x^2 +32x-12 by (x-2)



Answer 2

here is your answer

I hope it will help u