Question

using remainder theorem factorise x^2-13x-12

Answer 1

${x}^{2} - 13x - 12 \\ = {x}^{2} - 12x - 1x - 12 \\ = x(x - 12) - 1(x - 12) \\ = (x - 1)(x - 12)$

Answer 2

Hey friend, Harish here.

Here is your answer:

Let x³ - 13x -12 = p(x)

Then ,

p(-1) = (-1)³ - 13(-1) - 12

p(-1) = -1 + 13 -12 = 0

Therefore (x+1) is a factor. as p(-1) = 00

Then,

p(x) = (x+1) (x² -x -12)

⇒ p(x) = (x+1) (x² +3x -4x -12)

           = (x+1) (x(x+3)-4(x+3))

           = (x+1)(x+3)(x-4)
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Hope my answer is helpful to you,