Question

using remainder theorem factorise x cube minus 3 x square minus x minus plus 3​

Answer 1

Answer:

(x+1)(x-1)(x-3)

Step-by-step explanation:

p(x) = x³-3x²-x+3

By hit and trial , p(1) = 0

So , by remainder theorem (x-1) is one of its factor.

Now , dividing p(x) by x-1 , we get quotient as x²-2x-3

x²+x-3x-3

x(x+1)-3(x+1)

(x+1)(x-3)

These two are remaining two factors of p(x).

p(x) = (x-1)(x+1)(x-3)

= (x+1)(x-1)(x-3)

Answer 2

Answer:

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