Using remainder theorem, find remainder when:x3-ax2+2x-a is divided by x-a
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Apply remainder theorem
=>x – a =0
=> x = a
Replace x by a we get
=> x3 – ax2 + 6x – a
=>( a)3 -a(a)2 + 6(a) - a
=> a3sup> – a3 + 6a – a
=> 5a
Remainder is 5a
=>x – a =0
=> x = a
Replace x by a we get
=> x3 – ax2 + 6x – a
=>( a)3 -a(a)2 + 6(a) - a
=> a3sup> – a3 + 6a – a
=> 5a
Remainder is 5a
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