Question

using remainder theorem,find the remaainder when,x cube minus6x square plus 2x minus 4 is divided by 3x plus 2​

Answer 1

p(x)=x^3-6x^2+2x-4

g(x)=3x+2

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to find zero of p(x)

let value of g(x)=0

3x+2=0

x=2/3

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by remainder theorem

p(2/3)=(2/3)^3-6×(2/3)^2+2×2/3-4

=8/27-8/3+4/3-4

=8/27-4/3-4

=8-36/27-4

=-28/27-108/27

=-28-108/27

=-136/27

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