Question

Using remainder theorem. Find the remainder if x³-6x²+2x-4 is divided by 3x-1

Answer 1

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Here, g(x)=3x−1. To apply Remainder theorem, (3x−1) should be converted to (x−a) form.

∴3x−1=31(3x−1)=x−31∴g(x)=(x−31)

By remainder theorem, r(x)=p(a)=p(31)

p(x)=x3−6x2+2x−4⇒p(31)=(31)3−6(31)2+2(31)−4

=271−96+32−4=271−18+18−108=