Question

using remainder theorem find the remainder when (2x^4 + 6x^3 + 2x^2 + x - 8) is divided by (x+3)​

Answer 1

Step-by-step explanation:

If  x + 3 = 0

x = -3

f(x) = 2x4 – 6x3 + 2x2 – x + 3, [By remainder theorem]

f(x) = 2(-3)4 – 6(-3)3 + 2(- 3)2 – (- 3) + 3

= 2(-12)-6(-9)+2(-6)+3+3

= -24+54-12+3+3 = 24

Hence, required remainder = 24

Answer 2

Step-by-step explanation:

If x+3 = 0

x= -3

f( x) = 2(-3)^4 -6 (-3)^3 +2(-3)^2+(-3)-8

= 2(81) - 6(-27) + 2(9) + (-3) - 8

= 162 - 162 + 18 - 3 - 8

= 18 - 11

= 7 ans ..

hope its helpful .......