Using Remainder theorem, find the remainder when (3 − 62 + 9 + 3) is
divided by ( − 1)
Answers
Answered by
0
Answer:
p(x)=x
3
−6x
2
+9x+3
g(x)=x−1
x−1=0
x=1
p(1)=(1)
3
−6(1)
2
+9×1+3
=1−6+9+3
=−5+9+3
=4+3
=7
Answered by
0
Answer:47
Step-by-step explanation:
=(3-62+9+3)/-1
=(9+3+3-62)/-1
=(15-62)/-1
=-47/-1
=47
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