Question

using remainder theorem find the remainder when
f(x)= 2x³-5x²+3x-10 by (x-3)​

Answer 1

Step-by-step explanation:

$x - 3 = 0$

$x = 3$

Now we will keep the value of x in the place of x

$f(3)= 2(3)³-5(3)²+3(3)-10$

$f(3)=2 \times 21 - 5 \times 9 + 3 \times 3 - 10$

$f(3) = 42 - 45 + 9 - 10$

$f(3) = - 3 + 9 - 10$

$f(3) = - 3- 1$

$f(3) = - 4$

Answer 2

Answer:

-4

is answer

please mark as brilliant