Question

using remainder theorem find the remainder when f(x) is divided by g(x).
f(x)=x^24-x^19-2 g(x)=x+1

Answer 1

Pls the pic...
Your answer is there. ..
Hope it helps you...

Answer 2

zero of g(x)
x+1 = 0
x= (-1)
putting this in f(x)
${( - 1)}^{24} - {( - 1)}^{19} - 2 \\ = 1 - ( - 1) - 2 \\ = 1 + 1 - 2 \\ = 0$
${( - 1)}^{even} = 1 \\ {( - 1)}^{odd} = - 1$