Question

using remainder theorem find the remainder when f(x)=x^2+3x^2-5x+4 is divided by x+2​

Answer 1

Answer:

Given that,

$p(x)=x^{3} +3x^{2} -5x+4$

Zero of $(x-2)$ is  

$=x-2=0$

$=x=2$

substitute the value of $x$ in $p(x)$

$p(2) = (2)^3 + 3(2)^2 -5(2)+4$

$p(2) = 8 + 3(4) - 10 +4$

$p(2) = 8+12-10+4$

$p(2) = 14$

Remainder is $14$.

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