Question

Using remainder theorem, find the remainder when is p(x)= 2x^3+3x^2-11x-8 divided by 2x+1​

Answer 1

Answer:

Hii

Step-by-step explanation:

p{x}=2x3+3x2-11x-8

g{x}=2x+1

Therefore,2x+1=0 =>2x=-1 =>x=(-1)/2

p{(-1)/2}=2{(-1)/2}3+3{(-1)/2}2-11{(-1)/2}-8

p{(-1)/2}=(2+3+22-16)/4

           =11

Hence, 11 is a remainder of the polynomial.