Question

using remainder theorem find the remainder when p(x)=3x^3+5x-8 is divided by (x - 2)​

Answer 1

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Here is your Answer....

Given:

p(x) = 3x^3+5x-8

actually remainder theorem states that if (x-a) is the factor of p(x) or not then p(a) is equal to zero of the polynomial ( this means that the remainder will become zero or it gives us some value it is called as remainder)This method is the simple form for long division.

so here, (x-2) when divide with p(x)

Let ,

x - 2 = 0

x = 2

so,

p(x) = 3x^3+5x-8

p(2) = 3(2)^3 + 5(2)-8

p(2) = 3(8)+10-8

p(2) = 24+10-8

p(2) = 34-8

p(2) = 26

when p(x) is divided by (x-2) we get the remainder as 26 .

you can verify this by actual division.

Hope this is useful...