Question

Using remainder theorem find the remainder when x^ 3-6x^ 2+9x+3 is divided by x-1

Answer 1

Solution :-

We know that

\boxed{\bf CSA = \pi rl}

CSA=πrl

↠ CSA = π × 6 × 12

↠ CSA = π × 72

↠ CSA = 72π

∴ CSA is 72 π cm²

Answer 2

p(x)=x3−6x2+9x+3

g(x)=x−1

x−1=0

x=1

p(1)=(1)3−6(1)2+9×1+3

=1−6+9+3

=−5+9+3

=4+3

=7