Question

Using remainder theorem find the remainder when x cube + 3 X square + 3 X + 1 is divided by x minus one upon two

Answer 1

Answer:

p (x)= x^3+3x^2+3x+1

g(x)=x-2

Zero of the polynomials

x-2=0

x=2

p (2)=2^3+3 (2)^2+3 (2)+1

= +8+12+6+12

=27