Question

Using remainder theorem find the remainder when x³-3x²-5 is divided by ( x+3)​

Answer 1

Answer:

x = -3

-3^3 - 3 * -3^2 - 5

-27 - 3 * 9 - 5

-27 - 27 - 5

-59

hope it helps

Answer 2

Answer:

(-59)

Step-by-step explanation:

Let g(x)=(x+3)

and to find the zero of g(x) polynomial we have to let g(x)=0

or, (x+3)=0

or, x=(-3)

putting the value of x in p(x)=x³-3x²-5

or, p(-3)=(-3)³-3×(-3)²-5

=(-27)(-27)(-5)

=(-59)