Question

using remainder theorem find the remainder when y^3+3y^2+3y+1 s divided by y+1​

Answer 1

Answer:

0

Step-by-step explanation:

y+1=0    ; y=-1

put y=-1 in eq

y^3+3y^2+3y+1

=(-1)^3+3(-1)^2+3(-1)+1

=-1+3(1)-3+1

=-1+3-3+1

=0

Hence the Remainder is 0