Using remainder theorem, find the value of a if the division of x³+5x²-ax+b leaves remainder 2a
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p[x]=x3+5x2-ax+6=2
p[1]=1*1*1+5*1*2-a*1+6=2
1+10-a+6=2
17-a=2
-a=2-17
-a=-15
a=15
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