Question

Using remainder theorem, find the value of a if the division of
x + 5x2 – ax + 6 by (x - 1) leaves a remainder 7​

Answer 1

Answer:

Let us assume x + 3 = 0

Then, x = -3

Given, f(x) = 2x2 – 5x + 1

Now, substitute the value of x in f(x),

f(-3)= (2 × -32) – (5 × (-3)) + 1

= (2 × 9) – (-15) + 1

= 18 + 15 + 1

= 34

Therefore, the remainder is 34.

(ii) f(x) = 3x3 + 7x2 – 5x + 1

Solution:-

Let us assume x + 3 = 0

Then, x = -3

Given, f(x) = 3x3 + 7x2 – 5x + 1

Now, substitute the value of x in f(x),

f(-3)= (3 × -33) + (7 × -32) – (5 × -3) + 1

= (3 × -27) + (7 × 9) – (-15) + 1

= – 81 + 63 + 15 + 1

= -81 + 79

= -2

Therefore, the remainder is -2.

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Answer 2

Answer:

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