Question

Using remainder theorem, find the value of a if the division of x³ +5 x² -ax +6 by (x -1) leaves the

remainder 2

Answer 1

Heya,
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$f(x)$= $f(1)$
x = 1 
then,
        Putting value in EQUATION:-
 $x^{3}$ + $5x^{2}$ -ax + 6 = 2
1 + 5 -a +6 = 2 
-a = 2 -6 -5 -1
-a = 2 - 12
-a = -10 
a =5 

Hence a = 5 
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ANKIT