Question

Using Remainder Theorem, find the value of ‘m’ if mx³-2x²- 3 and

x³– mx²+ 5 leave the same remainder when divided by x – 2.​

Answer 1

Answer:

By reminder theorem x-2=0

x=2

let p(x)=mx^3-2x^2-3 q(x)=x^3-mx^2+5

=m(2)^3-2(2)^2-3 =(2)^3-m(2)^2+5

=8m-8-3 =8-4m+5

= 8m-11 -------> 1 =13-4m --------->2

Now by equating equation 1 and 2

8m-11=13-4m

8m+4m=13+11

12m= 24

m=24/12

m=2