Question

using remainder theorm, find the remainder when 5x^3-x^2+6x-2 is divided by 1-5x

Answer 1

Answer:

Step-by-step explanation:

By remainder theorem

Divisor = 1 - 5x

5x = 1

x = 1/5.......... (1)

So, p(x) =5x^3-x^2+6x-2

p(1/5) = 5(1/5)^3-(1/5)^2+6(1/5)-2

=5×1/125-1/25+6/5-2

5/125 - 1/25 + 6/5 - 2×5/1×5

BY equalizing the denominator ^

1/25 - 1/25 + 6/5 - 10/5

= 0 + 6 - 10/5

- 4/5

So,

Remainder is - 4/5

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