Question

using remainder theorm, find the value of a if the division of x^3+5x^2-ax+6 by (x-1) leaves remainder 2​

Answer 1

Answer:

Step-by-step explanation:

Let us assume x -1 = 0

Then, x = 1

Given, f(x) = x^3 + 5^x2 – ax + 6

Now, substitute the value of x in f(x),

f(1) = 13 + (5 × 12) – (a × 1) + 6

= 1 + 5 – a + 6

= 12 – a

From the question it is given that, remainder is 2a

So, 2a = 12 – a

2a + a = 12

3a = 12

a = 12/3

a = 4

Therefore, the value of a is 4.