Question

Using remainder theorum find the value of k if on dividing 2xcube +3xsqure - kx+5 by x-2 leaves a reminder 7.

Answer 1

Answer:

Step-by-step explanation:

f(x)=2x³+3x²-kx+5

g(x)=x-2

f(2)=2*(2)³+3*(2)²-k*2+5=7

    =(2*8)+(3*4)-2k+5=7

    =16+12+5-2k=7

    =33-2k=7

    =-2k=7-33

    =-2k=-26

    =k=13

so. k=13