Question

using remainder therom, find the remainder when:. (1) (x_6x2+9x+3) is divided by (x_1)​

Answer 1

Answer:

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Answer 2

Answer:

If $p(x)=(x-6{x}^2+9x+3)$ is divided by $x-1$, the remainder is $7$.

Step-by-step explanation:

Zero of $(x-1)$ :

$x-1=0$

$x=0+1$

$x=1$

By Remainder Theorem :

$p(x)=(x-6{x}^2+9x+3)$

$p(1)=[(1)-6{(1)}^2+9(1)+3]$

$p(1)=1-6+9+3$

$p(1)=7$

Hope it helps.