Question

Using remainder therom ,find the remainder when (2x^3-5x^2+9x-8) is devided by (x-3)

Answer 1

Therefore answer is 28

Answer 2

Heya ! Here is u r Ans >
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$= \frac{(2x {}^{3} - 5x {}^{2} + 9x - 8) }{x - 3}$

$= \frac{2x {}^{3} \times 5x {}^{2} + 9x - 8 }{x - 3}$

$= \frac{10x {}^{3} \times x {}^{2} + 9x - 8 }{x - 3}$

$= \frac{10x {}^{3 + 2} + 9x - 8 }{x - 3}$

$= \frac{10x {}^{5} + 9x - 8}{x - 3}$
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