Using remained theorem, find the value of k if on dividing 2x³ + 3x² - kx + 5 by x - 2, leaves a remainder 7.
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Step-by-step explanation:
\bf\huge\textbf{\underline{\underline{Accrording\:to\:the\:Question}}}AccrordingtotheQuestion
f(x) = 2x³ + 3x² - kx + 5.
f(x) is divided by x - 2 it leaves 7 as a remainder
f(x) = x - 2
f(x) ⇒ x = 2
\bf\huge\textbf{\underline{\underline{Put\:Value\:of\:x\:in\:Equation}}}PutValueofxinEquation
f(2) = 7
f(2) = 2(2)³ + 3(2)² - k(2) + 5
⇒ 7 = 16 + 12 - 2k + 5
⇒ 7 = 33 - 2k
⇒ -26 = -2k
⇒ k = 13.
\bf\huge{\boxed{\bigstar{\sf\:{Hence\:k\:=\:13}}}}★Hencek=13
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