using reminder theorem, find the reminder when (x³-3x²-5) is devided by (x+3)
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Answered by
1
Answer:
(-59)
Step-by-step explanation:
q(x) = x+3, also q(x) = 0
=> x+3 = 0
=> x = -3
p(x) = x³-3x²-5
Substituting (-3) at place of x,
p(-3) = (-3)³-3(-3)²-5 = -27-27-5 = (-59)
Therefore, the remainder is (-59).
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