Question

using repeated subtraction method find the HCF of 320,120,95​

Answer 1

Step-by-step explanation:

320, 120 and 95

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Let us take 320 & 120 first m = 320,

n = 120

m – n = 320 – 120 = 200

m = 200, n = 120

∴ m – n = 200 – 120 = 80

120 – 80 = 40

80 – 40 = 40

∴ m = w = 40 → HCF of 320, 120

Now let us find HCF of 40 & 95

m = 95, n = 40

∴ m – n = 95 – 40 = 55

55 – 40 = 15

40 – 15 = 25

25 – 15 = 10

15 – 10 = 5

HCF of 40 & 95 is 5

10 – 5 = 5

HCF of 320, 120 & 95 is 5

hope it helps you