Using ruler and compass only construct a rectangle each of whose diagonals measures 6cm and the diagonals intersect at an angle of 45°...
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Hey there !!
▶ Question :-
→ Using ruler and compass only construct a rectangle each of whose diagonals measures 6cm and the diagonals intersect at an angle of 45°.
▶ Solution :-
↪ Points to be remember :-
→ Diagonals of rectangle are equal in length.
→ Diagonals of rectangle bisect each other.
▶ Now, explanation for the construction :-
• Draw a line AB of 6cm .
• Now, make perpendicular bisector of line AB which is at point O.
• Then, from O draw an angle of 45° .
• Produce the angle of 45° back also.
• Now, cut the line of length 3cm on both side of 45° angle and marked as point C and D.
• Finally, join the line AC, CB, BD and AD.
✓✓ Therefore, the figure so obtained ACBD is rectangle ✓✓.
↪ For figure :-
✔✔ Hence, it is solved ✅✅.
THANKS
#BeBrainly.
▶ Question :-
→ Using ruler and compass only construct a rectangle each of whose diagonals measures 6cm and the diagonals intersect at an angle of 45°.
▶ Solution :-
↪ Points to be remember :-
→ Diagonals of rectangle are equal in length.
→ Diagonals of rectangle bisect each other.
▶ Now, explanation for the construction :-
• Draw a line AB of 6cm .
• Now, make perpendicular bisector of line AB which is at point O.
• Then, from O draw an angle of 45° .
• Produce the angle of 45° back also.
• Now, cut the line of length 3cm on both side of 45° angle and marked as point C and D.
• Finally, join the line AC, CB, BD and AD.
✓✓ Therefore, the figure so obtained ACBD is rectangle ✓✓.
↪ For figure :-
✔✔ Hence, it is solved ✅✅.
THANKS
#BeBrainly.
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Anonymous:
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