Using ruler and compasses only
construct a quadrilateral ABCD in whichAB = 4 cm BC = 7 cm angleA = angle C =105° and angle D= 60°
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Steps of construction:
(i) Draw a straight-line PQ, take a point A on it.
(ii) At A, construct ∠QAF = 60o
(iii) At A, draw AE ⊥ PQ from AE cut off AN = 3cm
(iv) Through N draw a straight line to PQ to meet AF at D.
(v) At D, draw AG ⊥ AD, from AG cut off AM = 4cm
(vi) Through M, draw at straight line parallel to AD to meet AQ in B and ND in C.
Then, ABCD is the required parallelogram
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