Question

Using s,p,d,f notations describe the orbital with the following quantum number a]n=0,1=0,m1=0,ms=+1/2 and b] n=1,1=0,m1=0,ms=-1/2

Answer 1

Here n= principal quantum number, l= azimuthal quantum number

 

(a) when n = 1, l = 0 (Given) The orbital is 1s. (can have maximum of 2 electron)

 

(b) For n = 3 and l = 1 The orbital is 3p. (can have maximum of 6 electrons).

 

(c) For n = 4 and l = 2 The orbital is 4d. (can have maximum of 10 electrons)

 

(d) For n = 4 and l = 3 The orbital is 4f. (can have maximum of 14 electrons)