Using second law of motion derive the relation between force and acceleration
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Heya.......!!!!
______________________________
Simplly force is a push / Pull which causes motion .
SI unit of force is => Newton ( N )
CGS unit of force => Dyne .
Force is a vector Quality .
• deriviation :-
F = dp / dt
p = mv
=> F = d / dt ( mv )
=> F = mdv / dt + vdm / dt
As m is the mass of body and mass is constant then dm / dt = 0 .
=> F = m dv/dt
*( dv / dt = a , acceleration ) .
➡ F = ma .
===============================
Hope It helps You ☺
______________________________
Simplly force is a push / Pull which causes motion .
SI unit of force is => Newton ( N )
CGS unit of force => Dyne .
Force is a vector Quality .
• deriviation :-
F = dp / dt
p = mv
=> F = d / dt ( mv )
=> F = mdv / dt + vdm / dt
As m is the mass of body and mass is constant then dm / dt = 0 .
=> F = m dv/dt
*( dv / dt = a , acceleration ) .
➡ F = ma .
===============================
Hope It helps You ☺
Mbhagat:
Thanqq
Answered by
1
Answer:
Consider a body of mass 'm' moving with initial velocity (u).Let F be a force acting on it for 't' second, so that the velocity changes to 'v'.
Initial momentum = =mu
Final momentum = =mv
change in momentum = = mv-mu
Rate of change of momentum =
According to second of of newton F
F
From equation of motion = a (acceleration)
Fma F = kma
Note : K is constant term.
Explanation:
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