Question

using section formula show that the point are (-3,-2),(5,2)and(1,0)are collinear​

Answer 1

Answer:

Yes,,given points are collinear...

Step-by-step explanation:

Suppose,, given points are A(-3,-2),B(5,2) & C(1,0).

We know that if the given points are collinear then,,

ar(∆ABC)=0 unit^2

Hence,,

ar(∆ABC)

$= \frac{1}{2} ( - 3(2 - 0) + 5(0 + 2) + 1( - 2 - 2)) \\ = \frac{1}{2} ( - 3 \times 2 + 5 \times 2 + 1 \times ( - 4)) \\ = \frac{1}{2} ( - 6 + 10 - 4) \\ = \frac{1}{2} ( - 10 + 10) \\ = \frac{1}{2} \times 0 \\ = 0 \: {u}^{2}$

We found that the area of triangle ABC is 0 unit square.So given points are collinear...

Hope it helps you

Answer 2

Answer:

The Asker has asked us to solve the Ques with SECTION FORMULA :

Therefore , let (5,2) divide the segment into (-3,-2) and (1,0) in the ratio k:1

I hope further u can solve ......

Hope it helps you !!!!