Question

. Using section formula, show that the points
A(2,-3,4), B (-1,2,1) and C 0,2 are collinear.​

Answer 1

Answer:

hy....

Step-by-step explanation:

The given points are A(2,−3,4),B(−1,2,1) and C(0,31,2)

Let P be a point that divides AB in the ratio k:1.

Using section formula, the coordinates of P are given by,

(k+1k(−1)+2,k+1k(2)−3,k+1k(1)+4)

Now, we will find the value of k at which point P coincides with point C.

⇒k+1−k+2=0, we get k=2

For k=2, the coordinates of point P are (0,31,2),

i.e., C(0,31,2) is a point that divides AB externally in the ratio 2:1 and is the same as point P

Hence, points A,B and C are collinear.

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Answer 2

Above is your answer thanks