using section formula show that the points A (2,-3,4),B(-1,2,1),C(0,1/3,2) are colinear
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let the point p divides AB in the ratio K:1 by section formula. k(-1)+2/(k+1), k(2)-3/(k+1), k(1)+4/(k+1).Now we find the value of k at which point p coincides with point c.By
anurag109:
after then, taking -k+2/(k+1)=0, we obtain k=2, c is a point that divides AB externally in the ratio 2:1 and is the same as point p. Hence, the point A,B,C are collinear.
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