Question

Using Shridhar Acharya method solve. x square +18x+32.

Answer 1

Step-by-step explanation:

x²+18x+32=0

x²+16x+2x+32=0

x=-16 and x=-2

Answer 2

$\fcolorbox{red}{aqua}{solution : - } \\ \\ \red { = > } {x}^{2} + 18x + 32 \\ \\ \underline \red{compare \: with} \: \: {a}^{2} + bx + c \: \\ \\ \underline \red{so} \\ \\ a = 1 \: \: \: \: b = 18 \: \: \: c \: = 32 \: \\ \\ x = \frac{ - b \: ± \: \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x = \frac{ - 18 \: ± \: \sqrt{ {18}^{2} - 4 \times1 \times 32} }{2 \times 1} \\ \\x = \frac{ - 18 \: ± \: \sqrt{ 324 - 128 } }{2 } \\ \\x = \frac{ - 18 \: ± \: \sqrt{ 196 } }{2 } \\ \\ x = \frac{ - 18 \: ± \: 14 }{2 } \\ \\x = \frac{ - 18 \: + 14\: }{2 } \: \: or \: x = \frac{ - 18 - 14}{2} \\ \\ x = - \frac{ 4}{2} \: \: or \: \: x = - \frac{32}{2} \\ \\ x = - 2 \: \: or \: \: x = - 16\\ \\ \fcolorbox{red}{white}{i \: hope \: it \: helps \: you.}$