Question

Using sin(A-B) =SinA CosB - CosA SinB
Value of sin 15° =​

Answer 1

Step-by-step explanation:

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Answer 2

$\bf{\blue{\bigstar}}$ Answer

$\bold{\bf{\red{sin(A-B)=sinA.cosB-cosA.sinB}}}$

$\bold{Now\;,\;sin15^0}\\\\\implies \bold{sin(45^0-30^0)}\\\\\implies \bold{sin45^0.cos30^0-cos45^0.sin30^0}\\\\\implies \bold{\frac{1}{\sqrt{2}}.\frac{\sqrt{3}}{2}-\frac{1}{\sqrt{2}} .\frac{1}{2} }\\\\\implies \bold{\frac{\sqrt{3}}{2\sqrt{2}}-\frac{1}{2\sqrt{2}} }\\\\\implies \bold{\bf{\blue{\frac{(\sqrt{3}-1)}{2\sqrt{2}} }}}$