Question

Using sitable identity find the ( 2a/3b + 3b/2a) square

Answer 1

Answer:

(2a -3b)^2 +(2a +3b)^2

using a^2 +b^2 =(a+b)^2 -2ab

=(2a-3b +2a +3b)^2 -2(2a-3b)(2a+3b)

using (a+b)(a-b)=a^2-b^2

=(4a)^2-2{(2a)^2-(3b)^2}

=16a^2-8a^2+18b^2

=8a^2+18b^2

Step-by-step explanation: