Question

using spd notation describe the orbital n=6 l=0 and n=3 l=2​

Answer 1

Here you are my friend the answer you are lookin for is

Here n= principal quantum number, l= azimuthal quantum number

(a) when n = 1, l = 0 (Given) The orbital is 1s. (can have maximum of 2 electron)

(b) For n = 3 and l = 1 The orbital is 3p. (can have maximum of 6 electrons).

(c) For n = 4 and l = 2 The orbital is 4d. (can have maximum of 10 electrons)

(d) For n = 4 and l = 3 The orbital is 4f. (can have maximum of 14 electrons)