Question

using square root table find the square root of 430 of the following numbers up to 3 place of drcimal​

Answer 1

Answer:

We know that 1^2 = 1 and 2^2 =4. This implies that the square root x of 3 should be such that 1 < x < 2. So, let 3^0.5 = ( 2 - h) where 0 < h < 1. => (2 - h)^2 = 3 => 4 -4h +h^2 = 3 => -4h < 3 - 4 ignoring h^2.