using standard formula expand
(2x-1/3y) '3
please help me
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Answer:
see this answer
Step-by-step explanation:
see,
(2x - 1/3y)³
= (2x)³ - [3 × (2x)² × 1/3y] + [3 × 2x × (1/3y)²] - (1/3y)³
= 8x³ - 4x/y + 2x/3y - 1/27y³
= 8x³ - 1/27y³ - 4x/y + 2x/y
hope it will help you
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