Question

Using Stock notation, represent the
following compounds :HAuCl4, Tl2O, FeO,
Fe2O3, CuI, CuO, MnO and MnO2.
Solution
By applying various rules of calculating
the oxidation number of the desired
element in a compound, the oxidation
number of each metallic element in its
compound is as follows:
HAuCl4 → Au has 3
Tl2O → Tl has 1
FeO → Fe has 2
Fe2O3 → Fe has 3
CuI → Cu has 1
CuO → Cu has 2
MnO → Mn has 2
MnO2 → Mn has 4
Therefore, these compounds may be
represented as:
HAu(III)Cl4, Tl2(I)O, Fe(II)O, Fe2(III)O3,
Cu(I)I, Cu(II)O, Mn(II)O, Mn(IV)O2.

In CuI

Cu has 1
how?
please explain

Answer 1

Answer:

By applying various rules of calculating the oxidation number of the desired element in a compound, the oxidation number of each metallic element in its compound is as follows:

HAuCl4 → Au has 3

Tl2O → Tl has 1

FeO → Fe has 2

Fe2O3 → Fe has 3

CuI → Cu has 1

CuO → Cu has 2

MnO → Mn has 2

MnO2 → Mn has 4

Therefore, these compounds may be represented as: HAu(III)Cl4, Tl2(I)O, Fe(II)O, Fe2(III)O3, Cu(I)I, Cu(II)O, Mn(II)O, Mn(IV)O2

Explanation:

Answer 2

Answer:

Fe2O3=(2X)+3(-2)=0

2X-6=0

2X=6

X=6/2

X=3