• Using substitution Euler's Equidimensional equations transform into an equation with constant coefficients. Answer A. 2-tang B. z=logx C. z=sinx D. 2=COSX
Answers
Answer:
The second‐order homogeneous Cauchy‐Euler equidimensional equation has the form
where a, b, and c are constants (and a ≠ 0). The quickest way to solve this linear equation is to is to substitute y = x m and solve for m. If y = x m , then
so substitution into the differential equation yields
Just as in the case of solving second‐order linear homogeneous equations with constant coefficients (by first setting y = e mx and then solving the resulting auxiliary quadratic equation for m), this process of solving the equidimensional equation also yields an auxiliary quadratic polynomial equation. The question here is, how is y = x m to be interpreted to give two linearly independent solutions (and thus the general solution) in each of the three cases for the roots of the resulting quadratic equation?
Case 1: The roots of (*) are real and distinct.
If the two roots are denoted m 1 and m 2, then the general solution of the second‐order homogeneous equidimensional differ‐ential equation in this case is
Case 2: The roots of (*) are real and identical.
If the double (repeated) root is denoted simply by m, then the general solution (for x > 0) of the homogeneous equidimensional differential equation in this case is
Case 3: The roots of (*) are distinct conjugate complex numbers.
If the roots are denoted r ± si, then the general solution of the homogeneous equidimensional differential equation in this case is
Example 1: Give the general solution of the equidimensional equation
Substitution of y = x m results in
Since the roots of the resulting quadratic equation are real and distinct (Case 1), both y = x 1 = x and y = x 3 are solutions and linearly independent, and the general solution of this homogeneous equation is