Math, asked by queensakshi74, 7 months ago

using substitution method solve 2x-7y = 1 and 4x+3y=15​

Answers

Answered by Imblank
2

Step-by-step explanation:

2x-7y=1

x=1+7y/2

4(1+7y/2)+3y=15

4(2+7y/2)+3y=15

(8+28y)/2+3y=15

(16+28y)/2+3y=15

(16+28y+6y)/2=15

16+34y = 30

34y = 30-16

34y = 14

y = 14/34

y = 7/17

Putting the value of y in eq 1

2x-7(7/17) = 1

2x - 49/17 = 1

2x = 1-49/17

2x = (17-49)/17

2x = -32/17

x = -16/17

x = -16/17

y = 7/17

Answered by jithinayalloor
2

Answer:

Step-by-step explanation:

2x-7y = 1

⇒2x=1+7y

⇒x=\frac{1+7y}{2}

4(\frac{1+7y}{2})+3y=15

⇒2+14y+3y=15

⇒17y=13

⇒y=13/17

4x+3(13/17)=15

4x=(-255+15)/17

4x=-240/17

x=-68/17

x=-4

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