Question

using suitable i dentities evalute (103)3

Answer 1

Answer:

${(100 + 3)}^{3} \\ = > {(a + b)}^{3} = {a}^{3} + {b}^{3} + 3 {a}^{2} b + 3a {b}^{2} \\ so \\ = {100}^{3} + {3}^{3} + 3( {100})^{2} .3 + 3 \times 100 \times {3}^{2} \\ = 1000000 + 27 + 90000 + 2700 \\ = 1092727$

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