Question

using suitable identites expand the following (x/3-3/y)^2

Answer 1

(x/3-3/y)²

on expanding=(xy-9/3y)²

= (xy-9)²/9y

=x²y²-18xy+81/9y²


Hope it helped u..

Answer 2

HEY MATE HERE IS YOUR ANSWER...


$( \frac{x}{3} - \frac{3}{y} )^{2} \\ using \: identity \: ({a - b})^{2} = {a}^{2} + {b}^{2} - 2ab \\ \frac{x}{3}^{2} + \frac{3}{y}^{2} - 2 \times \frac{x}{3} \times \frac{3}{y} \\ \frac{ {x}^{2} }{9} + \frac{9}{ {y}^{2} } - \frac{6x}{3y}$
HOPE IT HELPS YOU.