Using suitable identities , evaluate 56ka cube + 44ka cube
Answers
Answered by
0
Answer:
Step-by-step explanation:
(56^3)+(44^3)
a^3+b^3=(a+b)(a^2+b^2-ab)
=(56+44)((56^2)+(44^2)-56*44)
=(100)(3136+1936-2464)
=(100)(2608)
=260800
Answered by
0
Step-by-step explanation:
here,we use the identity(a+b){(56)^2+(44)^2-56*44
then it will,
(100)(3136+1936-2464)
Attachments:
Similar questions
Science,
4 months ago
Political Science,
4 months ago
Math,
9 months ago
Math,
1 year ago
Physics,
1 year ago
Environmental Sciences,
1 year ago