using suitable identities evaluate the following 105×95
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Required Answer:-
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- Identity I: (a + b)² = a²+ ²ab + b²
- Identity III: a² – b²= (a + b)(a – b)
- Identity IV: (x + a)(x + b) = x²+ (a + b) x + ab.
- Identity V: (a + b + c)² = a² + b² + c²+ 2ab + 2bc + 2ca.
- Identity VI: (a + b)³ = a³ + b³ + 3ab (a + b)
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As per the data given in the above question.
In the above question, it is given that,
The given data is ,
To evaluate the given value by identities,
Thus, identities is to compare one equation with other we get,
compare,
We get,
Hence we get the value as 9975.
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